tag:blogger.com,1999:blog-6489325605624459987.post1578170364767076933..comments2011-10-31T15:22:57.821-04:00Comments on Casual Math Puzzlers: Cyclic BaseballCaleb N.http://www.blogger.com/profile/06412691014953572832noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6489325605624459987.post-63799407468522409772011-05-04T12:55:35.370-04:002011-05-04T12:55:35.370-04:00My answer is:
p(hitting a natural cycle) / (# of ...My answer is:<br /><br />p(hitting a natural cycle) / (# of ways one can hit the cycle, or 4P4, or 4!)<br /><br />(.0175*.06*.015*.025) / 24 = 1.6406 E-8<br /><br /> = .0000016406%Kenhttps://www.blogger.com/profile/06222707745833150618noreply@blogger.comtag:blogger.com,1999:blog-6489325605624459987.post-4060985354529187642011-05-04T12:48:22.365-04:002011-05-04T12:48:22.365-04:00Here's a relevant blog thread, albeit using 20...Here's a relevant blog thread, albeit using 2010 data:<br />http://www.hardballtimes.com/main/article/the-odds-of-a-cycle/Kenhttps://www.blogger.com/profile/06222707745833150618noreply@blogger.com